01 / Starting from a reconstructed state
One possible present can lead to many modeled futures.
Lesson 14 gave us a conditional reconstruction law over possible January 2020 forest states. For this lesson, take one such state, call it X0, and fix a set of model parameters and one scenario. The stochastic model can now generate many future histories from that same starting point.
Some stems die. Others grow. New stems may enter the measured population. Different sampled outcomes produce different trajectories, even when the initial reconstruction and scenario are held fixed.
The model evaluates horizons of 1, 5, 10, and 20 years. These are simulated outcomes under a declared demographic law, not observed future forests.
02 / What changes during a modeled year?
Mortality, growth, and candidate entry update the cohort state.
Sample surviving stems using a probability derived from each cohort's mortality hazard.
Grow the surviving cohort diameters under one of two stochastic growth models.
Sample incoming counts using a stipulated entry-intensity law.
Population accounting
Current stems, minus deaths, plus entrants.
Nt is the current stem count, Dt+1 the number of modeled deaths, and Bt+1 the modeled entrants during the next step.
If a hypothetical modeled forest begins with 1,000 stems, loses 50, and gains 30, its next count is 980. The change in total count alone does not settle whether the system has satisfied its declared continuation requirements.
03 / Which future maintains the defined organization?
The specification checks structural support and how long an interruption lasts.
Paper V asks about two quantities at the annual checkpoints: basal area, BA(Xt), and juvenile support, J(Xt). The juvenile measure is a declared count proxy for woody stems below 10 cm diameter. The reference quantities come from the earlier census.
Structural requirements at a checkpoint
Both reference-relative bounds must be satisfied.
α controls the basal-area fraction; β controls the juvenile-support fraction. For the reported illustrative settings α = 0.75 and β = 0.4, the respective minimums are 75% and 40% of the reference quantities.
A prospective history must also satisfy the declared terminal structural conditions and a bound on its longest consecutive interruption. The parameter τ specifies the tolerated number of consecutive annual checkpoints below the structural criteria. For example, τ = 2 permits a qualifying interruption of at most two consecutive checkpoints.
These values are declared demonstration requirements. The study does not establish them as scientifically validated thresholds for the health of Harvard Forest.
04 / Candidate, lawful, viable
A sampled history must pass two different checks before it counts as viable.
First, the model's lawfulness check, LawfulG, assesses valid cohort counts and diameters, chronology, and population accounting. This verifies consistency with the declared computational rules; it does not establish biological correctness.
Second, a lawful history must pass the continuation criteria just described. A lawfully simulated future may lose the specified organization, or remain structurally insufficient for longer than allowed.
This is the candidate → lawful → viable architecture from Papers I and IV, now evaluated on a finite sample bank. Histories that fail either test retain their original probability weight in the accounting that follows.
05 / A bank of 64 possible futures
Here is a simple example we can calculate exactly.
Imagine a single conditional bank of 64 equally weighted future histories. The following counts are invented to explain the mathematics and are separate from the study's reported numerical results.
The viable-mass estimate for this equally weighted bank is 48/64 = 0.75. A quarter of the original conditional sample weight remains attached to histories that do not qualify as viable.
This estimate is a statement about the declared simulation bank. It is not an independently calibrated 75% ecological survival probability.
06 / Keep the denominator
Discarding failures would quietly change the probability question.
Share of the original probability mass assigned to viable continuation.
Share of the selected viable subset that is viable. The failures have disappeared from the denominator.
The second calculation is true as a conditional statement after we deliberately select successful futures. It cannot answer the original question about how much mass the model assigns to possible failure.
Total mass identity
Original probability is partitioned across all outcomes.
The four model-unlawful histories, twelve lawful noncontinuing histories, and forty-eight viable histories partition the whole 64-history candidate bank; their weights sum to one.
The viable subprobability measure retains the original weights of viable histories and restricts attention to them. Its total mass can be less than one. The failed histories no longer contribute to viable response capacity, while their excluded weight remains explicitly accounted for under the original law.
07 / The first question · Q₁
How much of the original probability mass supports a viable future?
Introduce a declared minimum viable probability θ (theta). The first adequacy question asks whether viable mass reaches this level.
Viable-mass adequacy
Q₁: does the viable mass reach θ?
For our hypothetical bank, mV = 0.75. A threshold θ = 0.75 is satisfied; θ = 0.80 is not. The comparison includes equality.
If the starting forest also presently realizes the declared organization, the same Q₁ adequacy answer becomes its full prospective Health answer for the specified scenario and horizon. That present-realization condition remains essential.
08 / The second question · Q₂
A viable future may still finish with a depleted juvenile reserve.
Paper V adds an additional terminal reserve requirement. For a simulated history γ, compare the terminal juvenile-support count with its initial value.
Terminal juvenile reserve ratio
A declared minimum ratio ρ identifies reserve-qualified futures.
When the initial juvenile-support denominator is zero, the paper defines this ratio as zero. A reserve-qualified history satisfies rJ(γ) ≥ ρ, using the declared reserve threshold ρ (rho).
Call the original probability mass of histories that are both viable and reserve-qualified mR(ρ). The second adequacy question is:
Reserve-qualified adequacy
Q₂: does reserve-qualified viable mass reach θ?
Every reserve-qualified viable history is also viable. Therefore mR ≤ mV, and requiring mR ≥ θ already implies the Q₁ mass condition.
Suppose 40 of the 48 viable histories in the invented bank also qualify for juvenile reserve. Then mR = 40/64 = 0.625. At θ = 0.75, Q₁ passes and Q₂ fails. The additional question detects something that the first does not require.